A determinant is a scalar value that can be computed from the elements of a square matrix and encapsulates certain properties of the matrix.
Example: A = | 3 2 | | 5 4 | Determinant, |A| = (3*4) - (2*5) = 2
A matrix is a rectangular arrangement of numbers in rows and columns. It is a fundamental concept in linear algebra.
Example: A = [ [1, 2], [3, 4] ] B = [ [5, 6], [7, 8] ] Addition, A + B = [ [6, 8], [10, 12] ]
The adjoint of a matrix is the transpose of its cofactor matrix, and the inverse is calculated using the formula:
A-1 = adj(A)/|A|, where |A| ≠ 0.
Example: A = [ [4, 7], [2, 6] ] Adj(A) = [ [6, -7], [-2, 4] ] |A| = (4*6) - (7*2) = 10 A-1 = 1/10 * [ [6, -7], [-2, 4] ]
The rank of a matrix is the maximum number of linearly independent rows or columns. The dependence of vectors occurs when a vector in a set can be expressed as a combination of other vectors.
Example: A = [ [1, 2, 3], [4, 5, 6], [7, 8, 9] ] After row reduction: Rank = 2
An eigenvector of a matrix A satisfies the equation A*v = λ*v, where λ is the eigenvalue.
Example: A = [ [2, 1], [1, 2] ] Eigenvalue λ = 3 Eigenvector v = [ [1], [1] ]
The Cayley-Hamilton theorem states that every square matrix satisfies its own characteristic equation.
Example: A = [ [1, 2], [3, 4] ] Characteristic Equation: λ2 - 5λ + 2 = 0 A satisfies this equation.
The limit at a point describes the value that a function approaches as the input approaches a specific point.
Example: f(x) = (x² - 1) / (x - 1) limx→1 f(x) = limx→1 (x + 1) = 2
The following properties simplify the computation of limits:
Example: f(x) = 2x, g(x) = x² limx→2 [f(x) + g(x)] = limx→2 2x + limx→2 x² = 4 + 4 = 8
Limits can be computed for different types of functions using direct substitution, factoring, rationalization, or L'Hôpital's Rule.
Example: f(x) = (x² - 9) / (x - 3) Factorize: (x - 3)(x + 3) / (x - 3) limx→3 f(x) = 3 + 3 = 6
A function is continuous at a point x = c if the following three conditions are satisfied:
Example: f(x) = x² At x = 2, f(2) = 4, limx→2 f(x) = 4. Hence, f(x) is continuous at x = 2.
A function is continuous over an interval if it is continuous at every point in that interval.
Example: f(x) = x² is continuous for all real numbers (-∞, ∞).
The Intermediate Value Theorem states that if a function is continuous on a closed interval [a, b], then for any value K between f(a) and f(b), there exists a value c in [a, b] such that f(c) = K.
Example: f(x) = x³ - x On [0, 2], f(0) = 0 and f(2) = 6. There exists a c ∈ (0, 2) such that f(c) = 3.
Discontinuities occur when a function is not continuous at a point. Types include:
Example: f(x) = 1/(x - 1) At x = 1, there is an infinite discontinuity.
The derivative of a function represents the rate at which the function changes with respect to its variable.
Example: f(x) = x² f'(x) = 2x
Example: f(x) = x², g(x) = x + 1 (fg)' = (2x)(x + 1) + (x²)(1) = 3x² + 2x
The chain rule is used to differentiate composite functions: (f(g(x)))' = f'(g(x)) · g'(x).
Example: f(x) = (2x + 3)² f'(x) = 2(2x + 3) · 2 = 4(2x + 3)
Composite functions are differentiated using the chain rule.
Example: f(x) = sin(2x) f'(x) = cos(2x) · 2 = 2cos(2x)
Logarithmic differentiation simplifies differentiation of functions by taking the natural log of both sides.
Example: f(x) = x^x ln(f(x)) = xln(x) f'(x) = x^x (1 + ln(x))
Rolle's Theorem: If f(a) = f(b) and f(x) is continuous and differentiable on [a, b], then there exists a point c in (a, b) such that f'(c) = 0.
Example: f(x) = x² - 4x + 4, on [0, 4] f'(x) = 2x - 4 At x = 2, f'(x) = 0
Mean Value Theorem: If f(x) is continuous and differentiable on [a, b], then there exists c in (a, b) such that:
f'(c) = [f(b) - f(a)] / (b - a)
Example: f(x) = x² on [1, 3] f'(c) = (f(3) - f(1)) / (3 - 1) = 4
Maclaurin's Series: Expansion at x = 0.
Example: f(x) = e^x Maclaurin: 1 + x + x²/2! + x³/3! + ...
Taylor's Series: Expansion around x = a.
Example: f(x) = ln(1 + x) Taylor: x - x²/2 + x³/3 - ...
L'Hôpital's Rule: For indeterminate forms (0/0 or ∞/∞), limx→c [f(x)/g(x)] = limx→c [f'(x)/g'(x)].
Example: limx→0 (sin(x)/x) = limx→0 (cos(x)/1) = 1
Maxima: Highest point of a function. Minima: Lowest point of a function.
Example: f(x) = x² - 4x + 3 f'(x) = 2x - 4 = 0 at x = 2 Maxima/Minima: f''(2) > 0, so Minima at x = 2
Curve tracing involves studying a curve's behavior by analyzing derivatives and plotting its graph.
Example: f(x) = x³ - 3x² + 2x Critical points: x = 0, x = 1, x = 2
Successive Differentiation: Repeatedly finding derivatives of a function.
Leibniz Theorem: Formula for nth derivative of a product of two functions.
Example: f(x) = e^x sin(x) fn(x) = e^x [sin(x + nπ/2)]
The integral as a limit of a sum defines the definite integral as the limit of Riemann sums, where a function is approximated by summing the areas of rectangles under its curve.
Example: ∫ f(x) dx from a to b = limn→∞ Σ [f(xi) Δx] where Δx = (b - a)/n
The Fundamental Theorem of Calculus links differentiation and integration. It states:
∫ f(x) dx from a to b = F(b) - F(a)
Example: f(x) = x² ∫ f(x) dx from 0 to 2 = F(2) - F(0) = (2³/3) - (0³/3) = 8/3
Indefinite integrals represent the family of all antiderivatives of a function.
Notation: ∫ f(x) dx = F(x) + C, where C is the constant of integration.
Example: f(x) = 2x ∫ f(x) dx = x² + C
Example: ∫ sin(2x) dx Let u = 2x, then du = 2 dx ∫ sin(u) du/2 = -cos(u)/2 + C = -cos(2x)/2 + C
Example: ∫ x e^x dx Let u = x, dv = e^x dx Then, ∫ x e^x dx = x e^x - ∫ e^x dx = x e^x - e^x + C
Example: ∫ (1 / (x² - 1)) dx Decompose: 1 / (x² - 1) = 1/2(1/(x-1) - 1/(x+1)) Integrate: ∫ (1/2)(1/(x-1) - 1/(x+1)) dx = (1/2) ln|x-1| - (1/2) ln|x+1| + C
Reduction formulae simplify the integration of higher powers of trigonometric functions.
Example: ∫ sinⁿ(x) dx = -(1/n) cos(x) sinⁿ⁻¹(x) + (n-1)/n ∫ sinⁿ⁻²(x) dx
Example: Γ(3) = ∫ x² e⁻ˣ dx from 0 to ∞ = 2
Example: B(1, 1) = ∫ t⁰ (1-t)⁰ dt from 0 to 1 = 1
A vector is a quantity that has both magnitude and direction. It is represented geometrically by an arrow pointing from one point to another.
Example: In 2D: v = (3, 4) In 3D: v = (1, 2, 3) Magnitude: |v| = √(x² + y²) in 2D, |v| = √(x² + y² + z²) in 3D
The double scalar product of two vectors, also known as the dot product, is given by:
v · w = |v||w|cos(θ), where θ is the angle between the vectors.
Properties:
Example: v = (3, 4), w = (1, 2) v · w = (3)(1) + (4)(2) = 11
The triple scalar product of three vectors v, w, and u is given by:
v · (w × u), where w × u is the vector cross product.
This represents the volume of the parallelepiped formed by the three vectors.
Example: v = (1, 0, 0), w = (0, 1, 0), u = (0, 0, 1) w × u = (1, 0, 0) v · (w × u) = 1 (Volume = 1 unit³)
The double vector product is given by:
(v × w) × u = (v · u)w - (w · u)v
This results in a vector that lies in the plane of w and u.
Example: v = (1, 0, 0), w = (0, 1, 0), u = (0, 0, 1) (v × w) × u = (0, 0, 1) × (0, 0, 1) = (0, 0, 0)
Area = |v × w|
Example: v = (1, 0, 0), w = (0, 1, 0) v × w = (0, 0, 1) Area = |(0, 0, 1)| = 1
Volume = |v · (w × u)|
Example: v = (1, 0, 0), w = (0, 1, 0), u = (0, 0, 1) Volume = |1| = 1